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Eiffelturm

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Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/eiffelturm/

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The following quantities appear in the problem: Länge \(\ell\) / Temperatur \(T\) / Längenausdehnungskoeffizient \(\alpha\) /

The following formulas must be used to solve the exercise: \(\ell = \ell_0 \cdot (1+ \alpha \cdot \Delta\vartheta) \quad \)

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Exercise:
Der Eiffelturm Eisen ist H hoch und soll im Sommer rund DHO höher sein als im Wer. Diskutieren Sie diese Behauptung mit einer passen Rechnung.

Solution:
Geg ssch H quad textHöhe Eiffelturm Delta h DHO DH quad textHöhenänderung sscalphaE aE quad textAusdehnungskoeffizient alpha % GesTemperaturänderung Delta thetaDelta thetasicelsius % Bei dieser Aufgabe macht es Sinn die notwige Temperaturänderung für die angegebene Längenänderung zu bestimmen. Damit kann die verlangte Diskussion geführt werden: % Delta h sscalphaE ssch Delta theta Delta theta DTF Delta theta fracDHaE H Delta theta DT approx DTS % Delta theta DTF &approx DTS % Jährliche Temperaturschwankungen im berechneten Bereich sind durchaus möglich. Allenfalls können die Schwankungen sogar grösser sein. Hingegen ist der Eiffelturm eine Eisenkonsturktion und hier wurde die Näherung einer langen Stange herangezogen.

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Contained in these collections:

Thermische Ausdehnung Festkörper - 1dim by TeXercises

25 | 31
Thermische Ausdehnung by dk

1 | 8

Attributes & Decorations

Branches	Thermal Expansion
Tags	längenausdehnung
Content image
Difficulty	(2, default)
Points	0 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	dk
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