Geometrische Zahlenfolgen IV
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
abcliste abc Die Seitenlängen inenander verschachtelter Quadrate bilden eine geometrische Folge. Wie lautet q wenn das erste Quadrat eine Seitenlänge von hat? abc Auch die Flächeninhalte der ausgefüllten Dreiecke bilden eine geometrische Folge. Warum? abcliste tikzpicture draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; scopexshiftcm filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- .. -- .. -- ; filldrawcolorwhite fillblack.. -- .. -- -- ..; filldrawcolorwhite fillblack.. -- . -- . -- ..; filldrawcolorwhite fillblack. -- .. -- . -- .; filldrawcolorwhite fillblack.. -- . -- .. -- ..; filldrawcolorwhite fillblack. -- .. -- .. -- .; filldrawcolorwhite fillblack. -- . -- .. -- .; filldrawcolorwhite fillblack. -- .. -- . -- .; draw -- -- -- -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw . -- .; draw . -- .; scope tikzpicture
Solution:
abcliste abc Am besten veranschaulicht man das Problem indem man ein paar Glieder der Folge aufschreibt. a_ a_ fracsqrtquad texttinyhalbe Länge der Diagonale des Anfangsquadrates a_ frac a_ fracsqrt Es lässt sich so leicht erkennen dass qfracsqrt sein muss. abc Man verwet die gleiche Strategie und schreibt einige Glieder auf um ein besseres Gefühl für die Sache zu bekommen. a_ a_ frac a_ frac a_ frac Man erkennt so dass in diesem Fall qfrac gilt. abcliste
abcliste abc Die Seitenlängen inenander verschachtelter Quadrate bilden eine geometrische Folge. Wie lautet q wenn das erste Quadrat eine Seitenlänge von hat? abc Auch die Flächeninhalte der ausgefüllten Dreiecke bilden eine geometrische Folge. Warum? abcliste tikzpicture draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; scopexshiftcm filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- .. -- .. -- ; filldrawcolorwhite fillblack.. -- .. -- -- ..; filldrawcolorwhite fillblack.. -- . -- . -- ..; filldrawcolorwhite fillblack. -- .. -- . -- .; filldrawcolorwhite fillblack.. -- . -- .. -- ..; filldrawcolorwhite fillblack. -- .. -- .. -- .; filldrawcolorwhite fillblack. -- . -- .. -- .; filldrawcolorwhite fillblack. -- .. -- . -- .; draw -- -- -- -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw . -- .; draw . -- .; scope tikzpicture
Solution:
abcliste abc Am besten veranschaulicht man das Problem indem man ein paar Glieder der Folge aufschreibt. a_ a_ fracsqrtquad texttinyhalbe Länge der Diagonale des Anfangsquadrates a_ frac a_ fracsqrt Es lässt sich so leicht erkennen dass qfracsqrt sein muss. abc Man verwet die gleiche Strategie und schreibt einige Glieder auf um ein besseres Gefühl für die Sache zu bekommen. a_ a_ frac a_ frac a_ frac Man erkennt so dass in diesem Fall qfrac gilt. abcliste
Meta Information
Exercise:
abcliste abc Die Seitenlängen inenander verschachtelter Quadrate bilden eine geometrische Folge. Wie lautet q wenn das erste Quadrat eine Seitenlänge von hat? abc Auch die Flächeninhalte der ausgefüllten Dreiecke bilden eine geometrische Folge. Warum? abcliste tikzpicture draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; scopexshiftcm filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- .. -- .. -- ; filldrawcolorwhite fillblack.. -- .. -- -- ..; filldrawcolorwhite fillblack.. -- . -- . -- ..; filldrawcolorwhite fillblack. -- .. -- . -- .; filldrawcolorwhite fillblack.. -- . -- .. -- ..; filldrawcolorwhite fillblack. -- .. -- .. -- .; filldrawcolorwhite fillblack. -- . -- .. -- .; filldrawcolorwhite fillblack. -- .. -- . -- .; draw -- -- -- -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw . -- .; draw . -- .; scope tikzpicture
Solution:
abcliste abc Am besten veranschaulicht man das Problem indem man ein paar Glieder der Folge aufschreibt. a_ a_ fracsqrtquad texttinyhalbe Länge der Diagonale des Anfangsquadrates a_ frac a_ fracsqrt Es lässt sich so leicht erkennen dass qfracsqrt sein muss. abc Man verwet die gleiche Strategie und schreibt einige Glieder auf um ein besseres Gefühl für die Sache zu bekommen. a_ a_ frac a_ frac a_ frac Man erkennt so dass in diesem Fall qfrac gilt. abcliste
abcliste abc Die Seitenlängen inenander verschachtelter Quadrate bilden eine geometrische Folge. Wie lautet q wenn das erste Quadrat eine Seitenlänge von hat? abc Auch die Flächeninhalte der ausgefüllten Dreiecke bilden eine geometrische Folge. Warum? abcliste tikzpicture draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw -- -- -- -- ; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; draw .. -- .. -- .. -- .. -- ..; draw . -- . -- . -- . -- .; scopexshiftcm filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- -- -- ; filldrawcolorwhite fillblack -- .. -- .. -- ; filldrawcolorwhite fillblack.. -- .. -- -- ..; filldrawcolorwhite fillblack.. -- . -- . -- ..; filldrawcolorwhite fillblack. -- .. -- . -- .; filldrawcolorwhite fillblack.. -- . -- .. -- ..; filldrawcolorwhite fillblack. -- .. -- .. -- .; filldrawcolorwhite fillblack. -- . -- .. -- .; filldrawcolorwhite fillblack. -- .. -- . -- .; draw -- -- -- -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw -- ; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw .. -- ..; draw .. -- ..; draw . -- .; draw . -- .; draw . -- .; draw . -- .; scope tikzpicture
Solution:
abcliste abc Am besten veranschaulicht man das Problem indem man ein paar Glieder der Folge aufschreibt. a_ a_ fracsqrtquad texttinyhalbe Länge der Diagonale des Anfangsquadrates a_ frac a_ fracsqrt Es lässt sich so leicht erkennen dass qfracsqrt sein muss. abc Man verwet die gleiche Strategie und schreibt einige Glieder auf um ein besseres Gefühl für die Sache zu bekommen. a_ a_ frac a_ frac a_ frac Man erkennt so dass in diesem Fall qfrac gilt. abcliste
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